How many moles of water are produced from the reaction of oxygen with four moles of propane (C3H8)? C3H8 + 5O2 --> 3CO2 + 4H2O

Explanation:

The reaction is:

C₃H₈ + 5O₂  →  3CO₂  +  4H₂O

We see, that the equation is ballanced.

As we have data from only one reactant, we assume the other is in excess.

Ratio is 1:4 (stoichiometry). We solve this, by a rule of three:

1 mol of propane can produce 4 moles of water

Then, 4 moles of propane, may produce

( 4 . 4 ) /1 = 16 moles of water can be made.

Remember, we always have to work with the limiting reactant.