Aluminum + lodine creates what reaction

Ibelieve y y even though i've only taken chemistry for one year

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

13 protons and 14 neutrons.  this also means that the amount of electrons also is 13 because electrons have the same amount as protons..the atomic number means the amount of protons (which effectively tells you the electrons) the atomic mass, tells you the amount of protons and neutrons in the nucleus.hope this .