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Chemistry, 09.02.2021 14:00 Tellyy8104

Use the information given below to calculate the enthalpy change for the reaction: C2H4(g) + H2O(g) → C2H5OH(l)

Rxn 1 H2O(l) → H2O(g) ΔH1 = +44 kJ/mol

Rxn 2 C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l)

ΔH2 = −1371 kJ/mol

3O2(g) → 2CO2(g) + 3H2O(l)

ΔH2 = −1371 kJ/mol C2H5OH(l)

Rxn 3 C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(l)

ΔH3 = −1409 kJ

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