Water (3010 g ) is heated until it just begins to boil. If the water absorbs 5.79x105 J of heat in the process, what was the initial temperature of the water?

54 °C

Explanation:

Step 1: Given and required data

Mass of water (m): 3010 gHeat absorbed (Q): 5.79 × 10⁵ JSpecific heat of water (c): 4.184 J/g.°CInitial temperature (T₁): ?Final temperature (T₂): 100 °C (Boiling point of water)

Step 2: Calculate the initial temperature of water

We will use the following expression.

Q = c × m × (T₂ - T₁)

5.79 × 10⁵ J = 4.184 J/g.°C × 3010 g × (100 °C - T₁)

T₁ = 54 °C

Following are the  advantages of the parametric equations: 1) they can be used to graph curves that are not functions, like the unit circle.2) the parameter can be used to represent the quantity that is  useful to  provide us with better information about the graph.3)  it is useful to convert between rectangular equations and parametric equations.with specific reference to chemistry,  parametric equations are employ for solving hydrogen and hydrogen-like ions, quantum mechanically. herein, cartesian coordinates are converted in spherical polar coordinates. the solution obtained, when plotted on spherical polar graph paper, provides visualization of atomic orbital such as s,p,d and f.