Consider the equations below A
CH (9) →C(s)+ 2H2(9) AH= 74,6 kJ
C(s) +2012(g) → CCI,(9) AH = -95.7 kJ
2H2(g) +2012(9) — 4HCl(g) AH, =-184.6 kJ
CH_(9)+ 4C12(g) → CC,(g) + 4HCI(g) AH= -205,7 kJ
B
Complete the following based on the diagram
D
Arrow A
✓
Arrow B
no
с
Arrow C
Arrow D

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