What volume (in L) of water vapor will be produced from the reaction of 4.95 L of ethane

(C2He)?

2C2H6(g) + 702(9) — 4CO2(g) + 6H2O(g)

14.85L of water are produced

Explanation:

Based on Avigadro's law, the volume is directly proportional to the moles of a gas.

Based on the equation:

2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(g)

2 moles of ethane produce 6 moles of H₂O.

Using Avogadro's law: 2L of ethane produce 6L of H₂O.

The addition of 4.95L of ethane are:

4.95L ethane * (6L H₂O / 2L C₂H₆) =