A mixture of krypton and argon gas is compressed from a volume of to a volume of , while the pressure is held constant at . Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

42556.5 J

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

A mixture of krypton and neon gas is compressed from a volume of 96.0L to a volume of 68.0L , while the pressure is held constant at 15.0atm . Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

The workdone on the gas can be calculated using below expresion,

W = - PΔV

Where P= Pressure of the mixture of the given gases

ΔV = Change in volume

Given;

Initial volume of the mixture= 96.0L

= 96.0L/ 1000= 0.096m³

Final volume of the mixture= 68.0L

= 68.0L/1000= 0.068m³

Pressure= 15.0atm, but we need to convert to N/m² for unit consistency.

1 atm= 101325 N/m²

15 atm = X

Cross multiply

X = (15×101325 )

X= 1519875 N/m²

P= 1519875 N/m²

W = - PΔV

W= - 1519875 × (0.068 - 0.096)

= - 1519875 × -0.028 m³

W= 42556.5 J

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

if you're asking what comes out, it's steam.