Molar Mass and Converting Grams to Moles Part 1: Calculate the Molar mass for the following compounds.
2. NH4Cl
1. Na SO,
3. KNO
4. BaCO3
5. Ca(OH)2
6. Na PO
7. (NH4)2Cr2O,
8. Al(ClO3)2
9. Li, N
10. Bas

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

just did the assignment and the answer was #1 +2 n

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .