A chemical process used to produce ethanol as a fuel additive was expected to produce 5,000 kilograms of ethanol based on the amounts of starting materials used, but only 4,760 kilograms were produced. What was the percent yield for ethanol in this process? A)1.09 percent B)4.80 percent C)95.2 percent D)105 percent

The percent yield for ethanol in this process is 95.2%

Explanation:

Yield is the ratio between the amount of product actually obtained in the reaction and the maximum amount of product that could have been obtained if the reagents had been completely consumed.

The theoretical yield is the yield is the maximum you can get in a reaction.

On the other hand, the actual performance shows what you really get in experimentation. It is generally less than the theoretical yield.

So, the percentage return is the actual return times the theoretical return multiplied by 100.

So, in this case the percentage yield will be calculated as:

percent yield=  95.2%

The percent yield for ethanol in this process is 95.2%

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles