How many grams of O2 are formed from 13.34 moles of KClO3? Provide your final answer rounded to two decimal places. 2 KClO3 → 2 KCl + 3 O2

640.32 g

Explanation:

2KClO₃ → 2KCl + 3O₂

First we convert KClO₃ moles to O₂ moles, using the stoichiometric coefficients:

Then we convert O₂ moles to grams, using its molar mass:

So 640.32 g of O₂ are formed from 13.34 moles of KClO₃.

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

i think   the answer is c hope i'm right