The following chemical reaction takes place in aqueous solution: SnSO 4 (aq)+2 NaOH(aq) Sn(OH) 2 (s)+Na 2 SO 4 (aq) Write the net tonic equation for this reaction.

SnSO4(aq) + 2KOH(aq) > Sn(OH)2(s) + K2SO4(aq)
Step 1: Write out the complete ionic equation:
Sn^2+(aq) + SO4^2-(aq) + 2K^+(aq) + 2OH^- > Sn(OH)2(s) + 2K^+(aq) + SO4^2-(aq)
Step 2: Cancel out the terms you find on both sides of the equation.
You cancel out SO4^2-(aq) and 2K^+(aq), which are on both side of the equation. Leaving
Sn^2+(aq) + 2OH^-(aq) > Sn(OH)2(s), this is your net ionic equation.

Adozen is 1221/12 = 1.751.75 x 12 = 21therefore, 1.75 is the answer.

A.