Based on the equation below, how many grams of nitrogen gas will be produced from the decomposition of one mole of sodium aside? Use a molar mass of 28.0 grams for nitrogen gas.

Mass of Nitrogen= 42 grams

Given

one mole of Sodium azide

Required

mass of Nitrogen

Solution

Reaction

The decomposition of one mol of sodium azide :

2 N a N 3 ( s ) → 2Na ( s ) + 3 N2 ( g )

From the equation, the mol ratio of N a N 3 ( s ) :  N2 ( g ) = 2 : 3, so mol N2 :

= 3/2 x mol N a N 3

= 3/2 x 1

= 1.5 moles

Mass of Nitrogen

= mol x molar mass

= 1.5 x 28 g/mol

= 42 grams

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.