3. Determine the [OH-] and pH of a solution that is [H3O+] = 3.7x10-2 M.

[OH⁻]= 2.7 x 10⁻¹³

pH = 1.431

Given

[H3O+] = 3.7x10⁻² M.

Required

the [OH-] and pH

Solution

pH = - log [H⁺]

pH = 2 - log 3.7

pH = 1.431

pOH = 14 - 1.431

pOH = 12.569

pOH = - log [OH⁻]

[OH⁻]= 2.7 x 10⁻¹³

or

[OH-][H3O+]=10⁻¹⁴

[OH-]=10⁻¹⁴ : 3.7 x 10⁻²

[OH-] = 2.7 x 10⁻¹³

the answer is:  

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