How much heat (in calories) must be applied to a 100 ml beaker filled with boiling water in order to vaporize the water?

540
5.4 x 104
800
8,000

Explanation:

Latent heat of vaporization is the amount of heat required to convert liquid to gas at atmospheric pressure.

Latent heat of vaporization =  540 cal/g

Volume of water = 100 ml

Density of water = 1 g/ml

Mass of water = ?

Mass of water = 100 g

Amount of heat required to vaporize 1 g of boiling water = 540 cal

Amount of heat required to vaporize 100 g of boiling water=

Thus must be applied to a 100 mL beaker filled with boiling water in order to vaporize the water.

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