A solution is prepared by dissolving 25.0 mL ethanol, CH3CH2OH (d=0.789 g/mL), in enough water to produce 250.0 mL solution. What is the molarity of ethanol in the solution?

The molarity of ethanol in the solution is 1.716M

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

Determine the mass of ethanol :

Mass of ethanol = 25 ml x 0.789 g/ml

Mass of ethanol = 19.725 g

Determine the moles of ethanol

Moles = Mass/Molar mass

Moles = 19.725 g/46 g/mol

Moles of ethanol = 0.429moles

Calculate the molarity using the formula below;

Molarity = Moles/Volume

Molarity = 0.429/0.25 L

Molarity = 1.716 M

Hence the molarity of ethanol in the solution is 1.716M

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The molarity = 1.716 M

Given

25 ml ethanol

d = 0.789 g/ml

250 ml solution

Required

The molarity

Solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

mass of ethanol :

= 25 ml x 0.789 g/ml

= 19.725 g

mol ethanol :

= 19.725 g : 46 g/mol

= 0.429

The molarity :

= 0.429 : 0.25 L

= 1.716 M

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