If 10.0 L of nitrogen gas reacts with 16.0 L of hydrogen gas, how many liters of ammonia gas (NH3) will be produced?

Volume of ammonia gas : 10.67 L

Given

10.0 L of nitrogen gas

16.0 L of hydrogen gas

Required

Volume of ammonia gas

Solution

Reaction

N₂ + 3H₂ ⇒ 2NH₃

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

Find limiting reactant :

N₂ : 10 : 1 = 10

H₂ : 16 : 3 = 5.3

H₂ as a limiting reactant

So volume of NH₃ based on H₂

= 2/3 x volume H₂

= 2/3 x 16 L

= 10.67 L

look at the !

pleaze mark brainliest!

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.