Aping pong ball with a mass of 2.20 grams rolls along a frictionless table with a velocity of 0.850 m/s. what is the momentum of the ping pong ball? 1.87 g m/s2.59 g m/s1.59 g m/s3.04 g m/s

The momentum of the ball is 1.87 g m/s.

Explanation:

Momentum of an object is defined as the product of mass of the object and the velocity of the object. Mathematically,

where,

p = momentum of the ball = ? g m/s

m = mass of the ball = 2.20 grams

v = velocity of the ball = 0.850 m/s

Putting values in above equation, we get:

Hence, the momentum of the ball is 1.87 g m/s.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;