PLEASE HELP ME, 20 POINTS How many atoms are in 25.00 g of Li.

Question 1 options:

2.393 x 1024 atoms of Li

1.333 x 1023 atoms of Li

2.16 x 1026 atoms of Li

2.17 x 1024 atoms of Li

How many grams is 2.393 x 1024 atoms of Cl

Question 2 options:

70.45 g Cl

140.9 g Cl

140.9 mole Cl

70.45 mole Cl

How many atoms are in 25.00 g of B.

Question 3 options:

1.393 x 1024 atoms of B

1.333 x 1023 atoms of B

2.16 x 1026 atoms of B

2.17 x 1024 atoms of B

How many grams is 2.393 x 1024 atoms of O

Question 4 options:

70.45 g O

140.9 g O

63.58 mole O

63.58 g O

Explanations:

Question 1: Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.

I am unsure of Question 2. I don't think it is mole though.

Question 3: Boron in 25.00-30.00 g is B. or D., but 25.00 g would be C.

Question 4: 2.393 x 1024 atoms of Oxygen is 63.58 mole O. I don't know for sure, but I think this is correct.

I am NOT professional. There is a chance I am incorrect. Please reply to me if I've made a mistake.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3