What is the mass of reactants in the following equation? N2 + 3H2 > 2NH3 Question 3 options: 34.05 amu 31.03 amu 30.02 amu 15.01 amu

34.06amu

Explanation:

The reaction expression is given  as:

          N₂   +   3H₂   →    2NH₃  

We are to find the mass of reactants in the equation given;

  Here:

      Mass of reactants  = 2(atomic mass of N) + 3[ 2 x atomic mass of H]

 Atomic mass of N  = 14.0067amu

 Atomic mass of H = 1.008amu

      Mass of reactants  = 2(14.0067) + 3(2 x 1.008)  = 34.06amu

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml