Calculate the mass of 29.6 L of fluorine gas at STP.

Mass = 25.08 g

Explanation:

Given data:

Volume of fluorine = 29.6 L

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Mass of fluorine = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

n = PV/RT

n = 1 atm × 29.6 L / 0.0821 atm.L/ mol.K × 273.15 K

n = 1.32 mol

Mass of fluorine:

Mass = number of moles × molar mass

Mass = 1.32 mol ×19 g/mol

Mass = 25.08 g

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