Please help!! (3-6 & 1-5)

part 1

3) 5.47 molecules

4) 11.15 moles

5) 2.95 × 10^23 molecules

6) 7670.9g

part2

1) 216000g

2) 5.71 molecules

3) 0.18 moles

4) 737.40g

5) 2.89×10^23 molecules

Explanation:

part 1

3) number of moles = (6.02 × 10^23)/11.0

=5.47molecules.

4) moles= (6.02 × 10^23)/(5.40×10^23)

= 11.15 moles

5) molar mass of NH3= 14+(3×1)= 14+3=17

number of molecules= (6.02 × 10^23) × 17/35

= (6.02 × 10^23)× 0.49 =2.95 × 10^23 molecules

6) molar mass of N2I6= (2×14) + (6×127)

= 28+762= 790g/mol

mass= 790 × (6.02 × 10^23)/(6.20×10^22)

=790× 9.71= 7670.9g

part 2

1) molar mass of CuBr= 64+80= 144g/mol

mass= 1500 × 144= 216000g

2) molecules = (6.02 × 10^23)/1.055

= 5.71 molecules

3) moles = (6.02 × 10^23)/(3.35×10^24)

= 0.18 moles

4) molar mass of SiO2= 28+ (2×16)= 28+32

=60gmol

mass= 60 × (6.02 × 10^23)/(4.90×10^22)

= 60× 12.29= 737.40g

5) molar mass of CH4= 12+(4×1)= 12+4=16g/mol

number of molecules= (6.02 × 10^23) × 16/33.6

= (6.02 × 10^23)× 0.48

= 2.89×10^23 molecules

56 moles of   lieter in chemistry

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.