A beaker with 150 ml of water is placed on a hot plate. The beginning temperature is 22 oC. After 5 minutes the temperature is 87 oC. What is the amount of thermal (heat)energy absorbed by the water. 150 ml = 150 grams specific heat of water = 4.184 J/goC. show work plzzz

The amount of thermal energy absorbed by the water : Q = 40,794 J

Given

150 ml water

Temperature = 22 °C to 87 °C

specific heat of water = 4.184 J/g°C

Required

Heat absorbed

Solution

Heat can be formulated :

Q = m.c.Δt

Q = 150 g x 4.184 J/g°C x (87-22)

Q = 40,794 J

mention the spill to the teacher clean the area and throw the broken pieces away

explanation:

- lead + phosphoric acid = hydrogen + lead(ii) phosphate