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2KCIO3 → 2KCI + 302
How many grams of potassium chloride are produced if 52 g of potassium chlorate decompose?

A )32 g KCI
B )19 g KCI
C)44 g KCI
D)1.5 g KCI

Mass of KCl : 32 g

Given

Reaction

2KCIO₃ → 2KCI + 30₂

52 g Potassium chlorate

Required

Mass of KCl

Solution

mol of KCIO₃ :

= mass : MW

= 52 g : 122.55 g/mol

= 0.424

From equation, mol KCl :

= 2/2 x mol KCIO₃

= 2/2 x 0.424

= 0.424

Mass KCl :

= mol x MW

= 0.424 x 74.5513 g/mol

= 31.6≈32 g

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.