6 Li + Zn3(PO4)2 > 2 Li3PO4 + 3 Zn If 48.6 g of zinc is made, how many moles of lithium phosphate are also made? moles

Moles of Lithium phosphate : 0.495

Given

6 Li + Zn₃(PO₄)₂ > 2 Li₃PO₄ + 3 Zn

Required

Moles of Lithium phosphate

Solution

moles of Zinc(Ar=65,38 g/mol) :

= mass : Ar

= 48.6 : 65.38

= 0.743

From equation, mol ratio of Zn :  Li₃PO₄ = 3 : 2, so mol  Li₃PO₄ :

= 2/3 x mol Zn

= 2/3 x 0.743

= 0.495

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.