Suppose a snack bar is burned in a calorimeter and heats 2,000 g water by 20 °C. How much heat energy was released? (Hint: Use the specific heat equation.) Give your answer in both joules and calorie

Explanation:

Remember that the key is the water so

using the formula q=m*s*deltT

We have the mass 2000g

we have the specific heat of water which is 1.00 cal/ g C

and the final temperature 20 C

Remember that delt T is the change in temperature meaning (Tfinal - Tinitial) Assuming that the water is at room  temperature (25 C)  before starting the reaction then

q= (2000 g)(1.00 cal/g C)(20-25)

q= -10, 000 cal  

if you want you can convert to joules by multiplying by 4.314 J

In more simpler terms - If all the heat released was absorbed by the water, and it takes 1 calorie of heat to raise

the temperature of 1 gram of water by 1°C that is a total of 20 times 2000 or 40,000 cal.

or 40 kilocalories. If you want it in joules, there are 4.184 joules to one calorie so it is

4.184 times 40 or 167.36 kilojoules.

Hope that helped

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.