2. How many joules are
required to change the temperature of 120 ml of
water by 5 °C?

Energy required : 2508 J

Given

V= 120 ml

Δt = 5°C

Required

Heat needed

Solution

Heat can be formulated :

Q = m.c.Δt

m = mass, g  

c = specific heat, joules / g °C  (water=4.18 J.g °C)

∆T = temperature difference, ° C / K  

mass water = 120 g(density = 1 g/ml)

Input the value :

Q = 120 g x 4.18 J.g °C x 5 °C

Q = 2508 J

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