Answer step by step please

The concentration of solution : 0.2 M

Given

5.6 g Potassium hydroxide(KOH)

500 ml of solution = 0.5 L

Required

The concentration

Solution

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

MW KOH = 39+16+1=56 g/mol

mol solute(KOH) :

= mass : MW KOH

= 5.6 : 56 g/mol

= 0.1

Molarity :

= 0.1 : 0.5

= 0.2 M

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"