Write the equilibrium expression for the following reaction. based upon the value of k, would there be more or less product in the equilibrium mixture?why? CaO(s)+CH4(g)+2H2O(g) = CaCO3(s)+4H2(g) kp=2344

As value of K is greater than 1, the reaction is forward driven.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. For equilibrium constant in terms of pressure , only gaseous reactants and products are considered.

For the given chemical reaction:

The expression for is written as:

As > 1, the reaction will be favoured in the forward direction and thus more products will be there.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.