Calculate the volume of a box which is 125 cm long, 37 cm wide, and 68 cm high. Report your answer with correct significant figures in cubic centimeters. please use significant figures! Calculate the volume of a box which is 423 cm long, 12 cm wide, and 25 cm high. have significant figures in cubic centimeters.

Suppose you are measuring the mass of a solid sample on a balance using a weigh boat. You record the data in a table. Mass of weigh boat 1.326 g Mass of weigh boat and sample 7.635 g What is the mass of the solid sample?

A graduated cylinder contains 10.00 mL water. A 14.74 g piece of aluminum is added to the water, and the volume rises to 15.46 mL. What is the density of the aluminum?

A 24.5 g sample of solution has a density of 0.768 g/mL. What is the sample volume (in mL)?

1. Volume of box is 314500 cm³.

2. Volume of box 126900 cm³.

3. Mass of sample is 6.309 g.

4. Density of aluminum is 2.7 g/mL.

5. Volume of sample is 31.9 mL.

Explanation:

1. Determination of the volume of the box

Length (L) = 125 cm

Width (W) = 37 cm

Height (H) = 68 cm

Volume (V) =?

V = L × W × H

V = 125 × 37 × 68

V = 314500 cm³

2. Determination of the volume of the box

Length (L) = 423 cm

Width (W) = 12 cm

Height (H) = 25 cm

Volume (V) =?

V = L × W × H

V = 423 × 12 × 25

V = 126900 cm³

3. Determination of the mass of the sample.

Mass of weigh boat = 1.326 g

Mass of weigh boat + Sample = 7.635 g Mass of the sample =?

Mass of Sample = (Mass of weigh boat + Sample) – (Mass of weigh boat)

Mass of Sample = 7.635 – 1.326

Mass of Sample = 6.309 g

4. Determination of the density of aluminum.

Volume of water = 10 mL

Mass of aluminum = 14.74 g

Volume of water + aluminum = 15.46 mL

Density of aluminum =?

Next, we shall determine the volume of aluminum. This can be obtained as follow:

Volume of water = 10 mL

Volume of water + aluminum = 15.46 mL

Volume of aluminum =?

Volume of aluminum = (Volume of water + aluminum) – (Volume of water)

Volume of aluminum = 15.46 – 10

Volume of aluminum = 5.46 mL

Finally, we shall determine the density of aluminum. This can be obtained as follow:

Mass of aluminum = 14.74 g

Volume of aluminum = 5.46 mL

Density of aluminum =?

Density = mass / volume

Density of aluminum = 14.74 / 5.46

Density of aluminum = 2.7 g/mL

5. Determination of the volume of sample.

Mass of sample = 24.5 g

Density of sample = 0.768 g/mL.

Volume of sample =?

Density = mass / volume

0.768 = 24.5 / volume of sample

Cross multiply

0.768 × Volume of sample = 24.5

Divide both side by 0.768

Volume of sample = 24.5 / 0.768

Volume of sample = 31.9 mL.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.