A sample of He has volume of 4.40 L at 555 torr and 33.0 C. Find the new pressure if the volume decreases to 3.50 L and the temperature increases to 44.0 C. 723 torr
504 torr
800. torr
612 torr

723 torr

Explanation:

Using the formula;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (torr)

V1 = initial volume (Litres)

T1 = initial temperature (°C)

P2 = final pressure (torr)

V2 = final volume (L)

T2 = final temperature (°C)

Based on the information provided in this question, V1 = 4.40L, P1 = 555 torr, T1 = 33.0 °C + 273 = 306K, V2 = 3.50 L, P2 = ?, T2 = 44.0 °C + 273 = 317K.

Using the formula above:

555 × 4.4/306 = P2 × 3.5/317

2442/306 = 3.5P2/317

Cross multiply;

2442 × 317 = 306 × 3.5P2

774114 = 1071 P2

P2 = 774114 ÷ 1071

P2 = 722.79

P2 = 723 Torr

i believe it is 40–40–20%

explanation:

there are two significant figures.