In very early attempts to classify organisms, the Greek philosopher, Aristotle, identified all animals as "air dwellers, land dwellers, or water dwellers". Under this system, all of the following organisms
would have been placed in the same group: Bat, grasshopper, eagle, butterfly, flying squirrel, and
sparrow. In the space below, construct a dichotomous key that can be used to identify these 6
animals,

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)