Hydrazine, N2H4, reacts with dinitrogen tetroxide, N2O4: 2 N2H4 (l) + N2O4 (g) → 4 H2O (l) + 3 N2 (g)

When 0.10 mol of hydrazone reacts with 0.10 mole of dinitrogen tetroxide, which of the following quantities would be consumed or produced?

Select one:
a. 0.10 mol N2O4
b. 0.05 mol N2O4
c. 0.39 mol N2
d. 0.40 mol H2O
please answer will give 5 stars

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as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

answer: mole of the gas

answer: mole of the gasexplanation: