Marine chemist exam in the mass percent composition of manganese sulfide compound from ocean floor he determined that 60.2% of this compound is sulfur determine the mole ratio between manganese and sulfur

Explanation:

Let the mass of the compound be 100g.

There are 60.2g of sulfur.

Moles of sulfur

= 60.2g / (32.07g/mol) = 1.877mol

There are 100g - 60.2g

= 39.8g of manganese.

Moles of manganese

= 39.8g / (54.94g/mol) = 0.724mol

Mole ratio of manganese to sulfur

= 0.724mol : 1.877mol = 1 : 2.5.

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.

ok whats the question if not i cannot you i need question and need a thing to answer