The temperature of 100 mL of a gas is increased from 20°C to 120°C while the pressure is held constant.
What is the new volume of the gas?

V₂ = 134.11 mL

Explanation:

Given data:

Initial volume = 100 mL

Initial temperature = 20°C (20+273.15 K = 293.15 K)

Final temperature = 120°C(120+273.15 K = 393.15 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 100 mL × 393.15 K / 293.15 K

V₂ = 39315 mL.K / 293.15 K

V₂ = 134.11 mL

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