How many atoms are there in 4430 grams of lithium (Li)?

3843.96 × 10²³ atoms

Explanation:

Given data:

Mass of Li = 4430 g

Number of atoms = ?

Solution:

We will calculate the number of moles first.

Number of moles =mass/molar mass

Number of moles = 4430 g/ 6.94 g/mol

Number of moles = 638.32 mol

1 mole contain 6.022 × 10²³ atoms

638.32 mol × 6.022 × 10²³ atoms / 1 mol

3843.96 × 10²³ atoms

the formula would be mgso4

mgso[subscript]4

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