A chemist adds 170.0mL of a ×3.75 x 10^−6/μmolL mercury(I) chloride Hg2Cl2 solution to a reaction flask. Calculate the mass in micrograms of mercury(I) chloride the chemist has added to the flask.

3 * 10^-4  μg

Explanation:

Molar mass of Hg2Cl2 = 472.09 g/mol

Now;

number of moles = mass/molar mass = concentration * volume

So;

n =m/M = CV

m = MCV

C = 3.75 x 10^−6/μmolL or 3.75 x 10^−12 molL-1

M =472.09 g/mol

V= 170.0mL

m = 3.75 x 10^−12  * 472.09 * 170.0/1000

m = 3 * 10^-10 g or 3 * 10^-4  μg

the answer to your question is c