Consider the following intermediate chemical equations. 2 equations. First: upper C (s) plus one half upper O subscript 2 (g) right arrow upper C upper O (g). Second: upper C upper O (g) plus one half upper O subscript 2 (g) right arrow upper C upper O subscript 2 (g).

How will oxygen appear in the final chemical equation?

Upper O subscript 2 (g). as a product

Upper O subscript 2 (g). as a reactant

O(g) as a product

2O(g) as a reactant

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.