Show how to work out the molar mass of Al2(SO3)3 294.15 g Al2(SO3)3

In which situation can a mixture always be called a solution

For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants. 4al(s)+3o2(g)→2al2o3(s) a) 1 molal, 1 mol o2 b) 4 molal, 2.6 mol o2 c) 16 molal, 13 mol o2 d) 7.4 molal, 6.5 mol o2

Balance the following reaction. as2s3 + 9o2 → 2as2o3 + so2