What is the mass of 4.32 mol GaI3? (3 points) Group of answer choices 1,720 g 1,230 g 455 g 1,950 g

Mass = 1946 g

Explanation:

Given data:

Number of moles of GaI₃ = 4.32 mol

Mass of GaI₃ = ?

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of GaI₃ = 450.44 g/mol

by putting values,

Mass = 4.32 mol × 450.44 g/mol

Mass = 1946 g

i think it is d. e because the next one is igneous.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%