Calculate the second volumes 980L at 71C and 107.2atm to 13C and 59.3atm

V₂ = 1473.03 L

Explanation:

Given data:

Initial volume = 980 L

Initial pressure = 107.2 atm

Initial temperature = 71 °C (71 +273.15 = 344.15 K)

Final temperature = 13°C (13+273.15 = 286.15K)

Final volume = ?

Final pressure = 59.3 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 107.2 atm × 980L × 286.15 K / 344.15 K×   59.3 atm

V₂ = 30061774.4 atm .L. K / 20408.095 atm. K

V₂ = 1473.03 L

2b2t

explanation:

2b2t

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.