Limestone CaCo3 decomposes into lime according to the equation below CaCo3 = CaO + CO2
(i) Balance the chemical equation above
(ii)what mass of limestone would produce 11.2 grams of lime?
Show your working

Mass = 19.0 g

Explanation:

Given data:

Mass of limestone react = ?

Mass of lime produced = 11.2 g

Solution:

Balanced chemical equation:

CaCO₃     →      CaO + CO₂

Number of moles of lime:

Number of moles = mass / molar mass

Molar mass of lime 56.1 g/mol

Number of moles = 11.2 g/ 56.1 g/mol

Number of moles = 0.19 mol

Now we will compare the moles of CaO and CaCO₃

                     CaO        :           CaCO₃

                       1             :             1

                     0.19          :          0.19

Mass of limestone react:

Mass = number of moles × molar mass

Mass = 0.19 mol × 100.1 g/mol

Mass = 19.0 g

the answer is the first option

explanation:

just googled it m8. not that hard

lol