What numbers balance Pb + H3PO4 —>Н2 + Pb3(Ро4)2

3Pb + 2H3PO4 —> 3H2 + Pb3(РO4)2

Explanation:

Pb + H3PO4 —>Н2 + Pb3(РO4)2

In order to balance the equation you must look at the number of elements already in the equation.

We see, on the left side, that:

Pb = 1, H = 3, P = 1, and O = 4

We see, on the right side, that:

Pb = 3, H = 2, P = 2, and O = 8

    Our goal is to balance these numbers so that they are equal. This is because of the law of conservation of matter states that "the amount of matter stays the same, even when matter changes form".

  We cannot change the subscripts, so we add coefficients.

3Pb + 2H3PO4 —> 3H2 + 1Pb3(РO4)2

Now, on the left side:

Pb = 3, H = 6, P = 2, and O = 8

And, on the right side:

Pb = 3, H = 6, P = 2, and O = 8

So, the balanced equation is: 3Pb + 2H3PO4 —> 3H2 + Pb3(РO4)2

*I hope that this helped you. Have a great day & good luck!

fe 55.85 g/mol and h2o 18.02 g/mol.