If an object is accelerating at a rate of 25 m/s2, how long (in seconds) will it take to reach a speed of 550 m/s? (Assume an initial velocity of zero.)

22s

Explanation:

Given parameters:

Acceleration  = 25m/s²

Final velocity = 550m/s

Initial velocity  = 0m/s

Unknown:

Time taken  = ?

Solution:

To solve this problem, we are going to use one of the motion equations:

                 v  = u + at

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

                  550 = 0 + 25 x t

                  550  = 25t

                    t  = 22s

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml