Sodium Phosphate reacts with calcium nitrate according to the following equation: 2 Na3PO4 + 3 Ca(NO3)2 - Ca3(PO4), + 6 NaNO3
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If 49.33 grams of sodium phosphate reacts, how many grams of Calcium Phosphate is
produced?

Mass = 46.52 g

Explanation:

Given data:

Mass of sodium phosphate react = 49.33 g

Mass of calcium phosphate produced = ?

Solution:

Chemical equation:

2Na₃PO₄ + 3Ca(NO₃)₂       →     Ca₃(PO₄)₂ + 6NaNO₃

Number of moles of Na₃PO₄:

Number of moles = mass/molar mass

Number of moles = 49.33 g/ 163.94 g/mol

Number of moles = 0.300 mol

now we will compare the moles of Na₃PO₄ and Ca₃(PO₄)₂

                Na₃PO₄         :             Ca₃(PO₄)₂

                    2                :               1

                 0.300           :             1/2×0.300 = 0.15

Mass of Ca₃(PO₄)₂:

Mass = number of moles × molar mass

Mass = 0.15 mol × 310.14 g/mol

Mass = 46.52 g

its mg hope this

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"