Write a balanced nuclear equation for the beta decay of Hg-202.

²⁰²Hg₈₀ > ²⁰²Tl₈₁ + ⁰₋₁e

Explanation:

The radioactive decay of the atom of an element by the emission of a beta-particle is equivalent to the splitting of a neutron in the nucleus of the radioactive element into an electron and a proton. The proton is retained by the nucleus whereas the electron is emitted as a beta-particle. This retention of the proton results in an increase of the atomic number by 1. A beta-particle is an electron. The electron is a very light particle and its loss makes no significant change in the mass number of the atom involved.

The beta decay of Hg-202 results in an increase of the atomic number from 8-0 to 81. Hence, Hg-202 is transformed to Tl-202. the balanced nuclear equation is given below:

²⁰²Hg₈₀ > ²⁰²Tl₈₁ + ⁰₋₁e

your answer would be a. 12.5 kg

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