a. A container has a volume of 20 m3 and initially it contains 25 kg of methane at a pressure of 10 bar. Determine the specific volume in m3/kg. b. Add 5 kg of Ethane to the tank. What is the specific volume of the mixture in m3/kg

a. 0.80 m³/kg

b. 0.67 m³/kg

Explanation:

a.

Step 1: Given data

Volume of the container (V): 20 m³

Mass of methane (m): 25 kg

Step 2: Calculate the specific volume (v) of methane

Specific volume is defined as the number of cubic meters occupied by one kilogram of matter.

v = V/m

v = 20 m³/25 kg = 0.80 m³/kg

b.

Step 1: Calculate the mass of the mixture

m = m(methane) + m(ethane)

m = 25 kg + 5 kg = 30 kg

Step 2: Calculate the specific volume (v) of the mixture

v = V/m

v = 20 m³/30 kg = 0.67 m³/kg

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

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