Calculate the empirical formula of lithium carbonate, if a sample contains 2.8g of lithium, 2.4g of carbon and 9.6g of oxygen.

Li₂CO₃

Explanation:

Given parameters:

Mass of lithium  = 2.8g

Mass of carbon  = 2.4g

Mass of oxygen  = 9.6g

Unknown:

Empirical formula of the compound  = ?

Solution:

The empirical formula is the simplest formula of a compound.

Elements                     Lithium                    Carbon              Oxygen

Mass                               2.8                           2.4                       9.6

Molar mass                      7                              12                         16

Number of

moles                           2.8/7                         2.4/12                   9.6/16

                                      0.4                              0.2                        0.6

Divide by the

smallest                      0.4/0.2                          0.2/0.2               0.6/0.2

                                          2                                  1                           3

The empirical formula is   Li₂CO₃

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.

its pwirhfpiwe

explanation:

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