PLEASE HELP!! Sulfur dioxide gas and oxygen gas react to produce gaseous sulfur trioxide. What mass of sulfur trioxide is produced when 125 g of sulfur dioxide reacts with 50.00 g of oxygen to produce sulfur trioxide as the only product.
2SO2(g) + O2(g) —> 2SO3(g)

Mass = 156.195 g

Explanation:

Given data:

Mass of SO₂ = 125 g

Mass of O₂ = 50.00 g

Mass of SO₃ produced = ?

Solution:

2SO₂ + O₂   →     2SO₃

Number of moles of SO₂:

Number of moles = mass/molar mass

Number of moles = 125 g/ 64.1 g/mol

Number of moles = 1.95 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 50.00 g/ 32 g/mol

Number of moles = 1.56 mol

Now we will compare the moles of SO₃ with SO₂ and O₂

                         O₂         ;          SO₃

                          1           ;            2

                         1.56      :          2/1×1.56 = 3.12 mol

                      SO₂        ;          SO₃

                          2          ;            2

                         1.95       :          1.95

Less number of moles of SO₃ are produced by SO₂ it will act as limiting reactant:

Mass of SO₃ :

Mass = number of moles × molar mass

Mass =  1.95 mol × 80.1 g/mol

Mass = 156.195 g

the volume of fluid displaced would equal the volume of the gas. use a gas syringe - this is a laboratory instrument that can be used to withdraw a certain volume of gas from a closed system or to measure the volume of gas from a chemical reaction.

plants need sunlight, water, and carbon dioxide to make food. plants use the raw materials of water, nutrients they absorb from soil, and carbon dioxide to make sugars the plant can use. energy from the sun and chlorophyll are also needed.