The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F. b. Calculate the pH at the halfway points to equivalence, B and D. [Key

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1.

Major Species at B:

1.

2.

Major Species at C:

1.

Major Species at D:

1.

2.

Major Species at E:

1.

Major Species at F:

1.

b) pH calculation:

At Halfway point B:

pH = pK + log[]/[H]

pH = pK = 6.35

Similarly, at halfway point D.  

At point D,

pH = pK + log [H]/[H2]

pH = pK = 10.33

the answer is 303.15 or 303