If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produced

69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

To calculate the moles, we use the equation:

moles of =

moles of =

moles of =

As 1 mole of reacts with 6 moles of

166 moles of   reacts with = moles of

As 1 mole of reacts with 12 moles of

166 moles of   reacts with = moles of

Thus is the limiting reagent.

As 1 mole of produces = 2 moles of cryolite

166 moles of   reacts with = moles of cryolite

Mass of cryolite =

Thus 69.72 kg of cryolite will be produced.